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Graphing Linear Inequalities
Students graph solution sets on number lines and coordinate planes, use boundary lines and shading, and interpret graphs of single and systems of linear inequalities.
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At a Glance
How does a graph show all ordered pairs or values that satisfy an inequality?
A graph shows every solution to an inequality. For a one-variable inequality, use a number line. Place an open circle at the boundary for because the boundary is not included. Place a closed circle for = because equality is included. Shade left for values less than the boundary and right for values greater than the boundary.
Example: x = -2 uses a closed circle at -2 and shades right. Compound inequalities may create a segment between two endpoints for and, or two rays for or.
A two-variable linear inequality such as y > 2x - 1 represents a half-plane. First graph the related boundary equation y = 2x - 1. Use a dashed boundary for and a solid boundary for =. Then choose a test point not on the line, often (0, 0). If the test point makes the original inequality true, shade the side containing it; otherwise shade the other side.
For y > mx + b, the solution region is above the boundary line. For y = 4 has a vertical solid boundary and shades right. Always verify with a test point rather than relying only on a memorized direction.
A system of inequalities requires all conditions to be satisfied. Graph each inequality and identify the overlapping shaded region. Points in the overlap are solutions to the system. A point on a solid boundary may be included, while a point on a dashed boundary is not.
Graphs are models. Label axes and units, interpret the boundary, and explain what the shaded region means in the real situation.
4,327 = 4,000 + 300 + 20 + 7
Learning Targets
- Use open circles or dashed lines for .
- Use closed circles or solid lines for =.
- Shade left or right on a number line.
- Graph the boundary equation for a two-variable inequality.
- Use a test point to choose the correct half-plane.
- Find overlapping regions for systems of inequalities.
- Interpret boundary points and shaded regions in context.
Interactive Vocabulary
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Worked Examples
Graph x≤3
Place a closed circle at 3.
Shade left because values are less than 3.
Include 3.
Graph y>2x−1
Draw y=2x−1 as a dashed line.
Test (0,0): 0>−1 is true.
Shade the side containing (0,0).
Common Questions
When is the endpoint filled in? When equality is included with =.
Why is a two-variable answer a region? Every ordered pair in the shaded half-plane satisfies the inequality.
How do I know which side to shade? Substitute a test point into the original inequality.
Can I always test (0, 0)? Use it unless it lies on the boundary line.
What solves a system of inequalities? Any point in the overlap that satisfies every inequality.
Common Misconceptions
Using an open circle for ≤ or ≥
Equal means the boundary is included.
Drawing a solid boundary for < or >
Strict inequalities exclude the boundary.
Shading from the slope alone
Test a point not on the boundary.
Watch, pause, and explain
Use the chapter markers, key vocabulary, and reflection prompts to stay actively engaged while you watch.
Practice until you can explain it
Move from a quick warm-up to guided practice, independent work, and deeper challenges.
Warm-Up
Graph x>−2.
Guided Practice
Graph x > 4. Answer: open circle at 4, shade right.
Graph x <= -3. Answer: closed circle at -3, shade left.
Write the inequality for an open circle at 2 shaded left. Answer: x < 2.
Graph -1 < x x + 2, use a dashed boundary and shade above.
For y 2x - 1? Answer: yes, so shade the side containing (0, 0).
Graph y >= x and y < -x + 4. Answer: shade the overlap above or on y = x and below y = -x + 4.
Independent Practice
Graph x≥1 and x<5 on one number line.
Graph y≥3x−2.
Determine whether (2,1) satisfies y<−x+4.
Challenge & Real-World Practice
Graph y≥x−3 and y<−2x+6 together. Identify two points in the overlap and verify both inequalities algebraically.
Nice work!
You completed the Practice It learning path.
IXL
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